Genetics- Part 1- Genes
Mendel
Mendel was an Austrian monk who taught natural science
and worked on plant breeding experiments.
He developed a basic understanding of genetics and inheritance.
Mendels Work
It took him 2 years to select the pea plant as his
subject.
He collected data for 10 years.
His sample sizes were large; he tabulated results from 28,000 pea plants.
He replicated his experiments.
He analyzed his data with statistics (probability theory).
Characteristics of Garden Peas:
Peas are easy to grow, and take little space.
They are inexpensive.
They have a short generation time compared to large animals so that a large number of
offspring can be obtained in a short amount of time.
They have some distinct characteristics that are easy to recognize. These
characteristics can be used when trying to determine patterns of inheritance.
They are easily self-fertilized or cross fertilized.
Traits Studied by Mendel
smooth or
wrinkled seeds
yellow or green seeds
red or white flowers
inflated or constricted pods
green or yellow pods
axial or terminal flowers
tall or dwarf plants
Mendels Crosses
Mendel used pure-breeding individuals in the first (P1)
generation.
P1
yellow X green
¯
F1
all yellow
¯
F2
3/4 yellow, 1/4 green
Mendels Results for 7 different crosses
P1 |
F1 |
F2 |
F2
ratio |
| smooth X wrinkled seeds |
all smooth |
5474 smooth
1850 wrinkled |
2.96:1 |
| yellow X green seeds |
all yellow |
6022 yellow
2001 green |
3.01:1 |
| axial X terminal flowers |
all axial |
651 axial
207 terminal |
3.14:1 |
| red X white flowers |
all red |
705 red
224 white |
3.15:1 |
| inflated X constricted pods |
all
inflated |
882 inflated
299 constricted |
2.95:1 |
| green X yellow pods |
all green |
428 green
152 yellow |
2.82:1 |
| tall X dwarf plants |
all tall |
787 tall
277 dwarf |
2.84:1 |
Conclusions from Mendel's Crosses
The F1 generation showed only one character that was present
in the P1. The other character reappeared in the F2 (25%).
The
sex of the parent did not matter.
The traits did not blend.
Mendel concluded that the F1 plants must contain 2 discrete factors, one for
each character. The character that was seen in the F1 is called dominant.
The character not seen in the F1 is called recessive.
Letters Can Represent Genes
The characteristics studied by Mendel were due to single genes. On the pair of chromosomes diagrammed below, the
letter "A" represents a gene for yellow seeds. The letter "a" on the homologous chromosome represents
a gene for green seeds. By convention, upper case letters are used to represent dominant
genes and lower case letters are used for recessive genes.

Because individuals are diploid, two letters can be used to
represent the genetic makeup of an individual. In the case of seed color, the following
three gene combinations are possible: AA, Aa, and aa.

Heterozygote (also called hybrid) refers to an individual that has two different
forms of the gene. Example: Aa
Homozygote refers to an individual that has two identical genes. Example: AA
or aa
A hybrid is a heterozygote. Example: Aa
Meiosis, Gamete Formation
The three diagrams below show metaphase I, anaphase I and telophase I in an "Aa" individual.
As can be seen in the diagrams, an "Aa" individual can produce gametes that have "A" and gametes that
have "a".
 |
Metaphase 1 |
 |
Anaphase 1 |
 |
Telophase 1 |
Principle of Segregation
Mendels principle of segregation states that paired
factors (genes) separate during gamete
formation (meiosis). Because
the pair of genes (Aa, AA, or aa) separate, one daughter cell will contain
one gene and the other will contain the other gene. (See diagram above.)
Gametes
Because pairs of chromosomes separate during meiosis I, gametes
are haploid, that is, they carry
only one copy of each chromosome. An Aa individual therefore produces two kinds of gametes: A and a.

Below: An "AA" individual produces all "A" gametes.
Similarly, an "aa" individual produces all "a" gametes.

Individual (genotype) |
Type of gametes produced |
AA |
all gametes will contain an
"A" |
Aa |
1/2 will contain
"A" and 1/2 will contain "a" |
aa |
all "a" gametes |
Punnett Squares
Suppose that an "Aa" individual is crossed with another "Aa"
individual. One will produce "A" eggs and "a" eggs. The
other will produce "A" sperm and "a" sperm. What are all
of the possible combinations of eggs and sperm? A Punnett square can be used
to show all of these combinations.
The Punnett square in the diagram below is used to show between two Aa
individuals.

The square below is used for this cross: AA X Aa.

One half of the offspring produced by
this cross will be AA, the other half will be Aa.
The cross can also be written as shown below because the
AA parent can produce only one kind of gamete (all A).

A Closer look at Mendels Crosses
(One Gene Locus)
Y = yellow y = green
P1 YY X yy
¯
F1
Yy
Yy X Yy
¬
A cross between two individuals that are heterozygous for a trait is
called a monohybrid cross.
F2 The above cross is illustrated below.

The genetic makeup of P1 plants was different from that of
F1 because the P1 plants were true breeding and the F1
plants were not. The genetic makeup of an individual is referred to as its genotype.
Because the plants are diploid, two letters can be used to write the
genotype.
In this case, the genotype of the P1 plants was YY; the genotype
of the F1
plants was Yy.
The characteristics of an individual are its phenotpye.
This word refers to what the individual looks like so ddjectives are used to
write the phenotype. For example, "yellow" or "tall" are
phenotypes.
The yellow P1 plants looked like the F1; they had the
same phenotype but different genotypes.
An individual with a recessive phenotype has two recessive genes. A
dominant phenotype results from either one or two dominant genes. In the
cross above, YY or Yy are yellow; yy is green. The phenotype ratio in the F2
is 3 yellow:1 green. The genotype ratio is 1YY:2Yy:1yy.
| Genotype |
Phenotype |
| AA or Aa |
Yellow |
| aa |
Green |
Other Crosses
S = smooth s = wrinkled
P1 SS X ss
¯
F1 Ss
Ss X Ss

F2 genotype ratio = 1:2:1 (1SS :
2Ss : 1ss)
phenotype ratio = 3:1 (3Smooth : 1 wrinkled)
F = full f = constricted
P1 FF X ff
¯
F1 Ff
Ff X Ff

F2 genotype ratio = 1:2:1 (1FF : 2Ff : 1ff)
phenotype ratio = 3:1 (3full: 1 constricted)
An allele is a gene that has more than one form. Each of
the forms is referred to as an allele. For example, the gene for red flowers and the gene for white flowers are two
different alleles.
A locus (plural: loci) is the location of a gene on a chromosome. The
gene for red flowers and the gene for white flowers are two different alleles at the same
locus. A single chromosome can have a gene for white flowers or a gene for red
flowers but not both.
There are two loci illustrated below, one is for flower color and
the other is for stem length. Flower color has five alleles and stem length has
two.

Practice
Crosses
Let " A" represent the allele for yellow seeds and " a"
represent the allele for green seeds. For each cross below, give the genotype of
the gametes and the expected genotypes and phenotypes in the offspring.
| Cross |
Gametes
1st parent |
Gametes
2nd parent |
Genotypes |
Phenotypes |
| AA X AA |
|
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| AA X Aa |
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| AA X aa |
|
|
|
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| Aa X Aa |
|
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| Aa X aa |
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| aa X aa |
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Click
here to view the answers.
Sickle-cell anemia is an abnormality of hemoglobin, the molecule that
carries oxygen in our blood. Red blood cells of affected individuals often
become distorted in shape, they then may break down or clog blood vessels causing pain,
poor circulation, jaundice, anemia, internal hemorrhaging, low resistance, and damage to
internal organs.
This condition is caused by a recessive gene.
A = normal
hemoglobin
a = sickle-cell hemoglobin
AA = normal
Aa = normal (called sickle-cell trait)
aa = sickle-cell anemia
A man with sickle-cell trait marries a normal woman. What is the probability that their
children will have sickle-cell trait?
If both parents have sickle-cell trait, what percentage of their children will:
have a normal phenotype?
have sickle-cell trait?
have sickle-cell anemia?
let A = red
a = white
Is a red flower AA or Aa?
Solution: cross it with aa
P1 A? X aa
The A? individual can produce these kinds of gametes: "A" and "?"
gametes: A, ? and a
F1 Aa and ?a
If the ?a individual is red, then ? = A. If it is white, then ? = a.
Should There Be Fewer Recessive
Alleles?
The population model described above predicts that gene
frequencies will not change from one generation to the next even if there are more
recessive alleles.
There is sometimes a misconception among students beginning to study genetics
that dominant traits are more common than recessive traits. Sometimes
this is true, sometimes it is not. For some traits, the dominant is more common;
for other traits, the recessive is more common. For
example, blood type O is recessive and is the most common type of blood.
Huntington's disease (a disease of the nervous system) is caused by a dominant gene and
the normal gene is recessive. Fortunately, most people are recessive; the
dominant is uncommon.
The misconception comes from the observation that in a cross of Aa X
Aa, 3/4 of the offspring will show the dominant characteristic. However, the 3:1
ratio comes only if the parents are both Aa. If there are
many recessive genes in a population, then most matings are likely to be aa X aa
and most
offspring will be aa.
In nature, natural selection may favor one- either the dominant or the
recessive- and that one will become more common over time. Other forces such as
genetic drift may also cause one or the other allele to become more common. In
the absence of forces that change gene frequencies, there is no reason to expect
dominant genes to be more common.
Probability
Multiplicative Rule
The probability of two or more independent
events occurring is equal to the product of their probabilities.
Example: What is the probability of tossing a coin two times and getting
a heads both times?
Solution: The probability of getting a heads on one coin is 1/2. The
probability of getting a heads on the second coin does not depend on the outcome of the
first coin, so the multiplicative rule is used. The probability of getting a heads on two
coins is 1/2 X 1/2 = 1/4.
Additive Rule
The probability of two or more mutually exclusive
events occurring is equal to the sum of their probabilities.
What is the probability that a student will get an “A” or a “B”
in a class if students generally earn the following grades:
A = 10% (or 0.10)
B = 35% (or 0.35)
C = 45%
D = 10%
Solution: In this example, the two outcomes (getting an "A" or getting a
"B") are mutually exclusive because you can only get one or the other. The
additive rule is used to determine the overall probability of getting an "A" or
a "B". 10% + 35% = 45% (or 0.10 + 0.35 = 0.45).
Consider Two Loci at the Same Time
Genes that are on different chromosomes assort independently.
The following are four different metaphase I allignment patterns that are possible for a
hypothetical species with a diploid chromosome number of 6.

The alignment pattern shown in the diagram below will produce Sy and sY
gametes.

The alignment pattern shown in this diagram will produce SY and sy
gametes.

Both of the patterns illustrated above are possible
because S and Y are located on different chromosomes.
The table below shows the kinds of gametes that can be
produced by several different kinds of genotypes. Each gene locus (A and B) is
on a different chromosome.
| Individual |
Gametes |
| AABB |
AB |
| AABb |
AB, Ab |
| AaBB |
AB, aB |
| AaBb |
AB, Ab, aB, ab |
| Aabb |
Ab, ab |
| AAbb |
Ab |
| aaBB |
aB |
| aaBb |
aB, ab |
| aabb |
ab |
let A = red, a = white
let B = smooth, b = wrinkled
The table below shows possible genotypes and phenotypes.
| Genotype |
Phenotype |
| AABB |
red, smooth |
| AABb |
red, smooth |
| AaBB |
red, smooth |
| AaBb |
red, smooth |
| Aabb |
red, wrinkled |
| AAbb |
red, wrinkled |
| aaBB |
white, smooth |
| aaBb |
white, smooth |
| aabb |
white, wrinkled |
In peas, the locus for seed texture
(smooth or wrinkled) and seed color (yellow or green) are on two different chromosomes so
they assort independently.
Suppose that they are on the same chromosome as indicated in the diagram
below. Independent assortment will not occur because the "S" gene is on the same
chromosome as the "y" gene. Similarly, the "s" gene is on the same
chromosome as the "Y" gene. Unless crossing-over occurs, "S" will
always be found with a "y" and "s" will be found if there is a
"Y".

Mendel studied seven different characteristics in
peas. Each of these characteristics are on different chromosomes, so they assort
independently.
Example: Two Gene Loci
Let S = smooth, s
= wrinkled
Let Y = yellow, y = green
P1 SMOOTH, YELLOW X
wrinkled, green
genotypes: SSYY ssyy
gametes: SY sy
¯
F1 SMOOTH, YELLOW X SMOOTH
YELLOW
genotypes: SsYy X SsYy ¬
A cross between two individuals that are heterozygous for two gene loci is
called a dihybrid cross.
gametes: SY, Sy, sY, sy
¯
F2

Mendel's Results
| SMOOTH, YELLOW |
315 |
| SMOOTH,
green |
108 |
| wrinkled, YELLOW |
101 |
| wrinkled,
green |
32
|
|
556 |
TRAIT 1, TRAIT 2 X trait 1, trait 2
(upper case traits are dominant)
9 - TRAIT 1 and TRAIT 2 expressed (A-B-)
3 - TRAIT 1 expressed (A-bb)
3 - TRAIT 2 expressed (aaB-)
1 - No dominant traits expressed (all aabb)
A dihybrid cross is two monohybrid crosses
Remember that each of the individual traits in the dihybrid
cross above behaves as a monohybrid cross, that is, they will produce a 3:1 phenotype
ratio in the offspring.
SMOOTH X wrinkled
Refer to the F2 data for the SMOOTH, YELLOW X
wrinkled, green cross above.
The number of smooth offspring was 315 + 108 = 423.
The number of wrinkled was 101 + 32 = 133.
The ratio of smooth to wrinkled is therefore 423:133 or approximately 3:1.
YELLOW X green
yellow = 315 + 101 = 416
green = 108 + 32 = 140
ratio = 416:140 or approximately 3:1
Combining Probabilities
9:3:3:1 can be obtained in a dihybrid cross by first
calculating probabilities for two monohybrid crosses and then combining their
probabilities.
probability of round = 3/4
probability of wrinkled = 1/4
probability of yellow = 3/4
probability of green = 1/4
probability of round and yellow =
3/4 X 3/4 = 9/16
probability of round and green = 3/4
X 1/4 = 3/16
probability of wrinkled and yellow =
1/4 X 3/4 = 3/16
probability of wrinkled and green =
1/4 X 1/4 = 1/16
The following steps can be used to determine the expected number of
offspring from any cross.
1. Determine the kinds of gametes that
can be produced by each parent.
2. Determine all of the possible combinations of gametes that can be
produced. A Punnett square may be useful for this.
If you use a Punnett square, the gametes of one parent are written across
the top and the gametes of the other parent written on one side. The number
of cells in the square is therefore equal to the number of gametes that one
parent can produce multiplied by the number of gametes that the other parent
can produce.
Example:
Let T = tall, t = short
F = inflated, f = constricted
List the phenotypes produced by the following cross:
TtFf X ttFf
Step 1: List the kind of gametes produced by each parent.
TtFf can produced TF, Tf, tF and tf.
ttFf can produce tF and tf.
Step 2: Construct a Punnett square.

The Punnett square above shows that eight different genotypes are
produced. The phenotype for each is listed in the table below.
| Genotype |
Phenotype |
| tTFF, tTFf, tTfF |
tall, inflated |
| tTff |
tall constricted |
| ttFF, ttFf, ttfF |
short inflated |
| ttff |
short, constricted |
Y = yellow
R = red
y = green
r = white
What is the genotype of a plant with yellow seeds and red flowers?
In the cross below, the symbols "-" and "?" represent unknown
alleles. "-" is either "Y" or "y". "?"
is either "R" or "r".
The genotype of a plant with yellow seeds and red flowers is "Y-R?".
Cross it with yyrr to find out the "-" and "?" alleles.
Y-R? X yyrr
gametes: YR, Y?, -R, -? (parent 1) and yr (parent 2)

If the unknown alleles (- and ?) are recessive, the phenotype ratio will
be 1:1:1:1.
In the cases that are discussed above, blending does not occur. Flowers
are either red or white but are never pink. Seeds are either yellow or green
but not yellowish-green. In these cases, if a dominant gene is present, it
is expressed. Some genes, however are neither dominant nor recessive and
when mixed, blending occurs.
Example: Snapdragons
A = Red flowers A' = white flowers
A heterozygote (AA') is pink.
Up to this point, we have discussed two possible alleles
for any gene locus. For example, at the flower color locus, there is either the red
or the white allele (A or a). With human blood types, there are three alleles: A, B,
or O. This is referred to as multiple alleles.
I is dominant to i.
There are two forms of I: IA and IB but only one form of i.
6 possible genotypes, 4 phenotypes:
IAIA and IAi
= blood type A
IBIB and IBi
= blood type B
IAIB = blood type AB
i i = blood type O
People with blood type A have a specific kind of carbohydrate chain on the surface of
their red blood cell. The carbohydrate chain is attached to a membrane protein or lipid.
Blood type B cells have have a different carbohydrate chain. Type AB cells have both A and
B chains. IA and IB are codominant because both
phenotypes are expressed; there is no blending
Codominance is different than Incomplete dominance (blending).
Genes that affect more than one trait are called pleiotropic.
For example, people with Marfan syndrome may be tall, thin, have long legs, arms and
fingers, and may be nearsighted. Their connective tissue is defective. If
unrepaired, the connective tissue surrounding the aorta will eventually rupture and kill
the person. All of these characteristics are due to a single gene.
Alleles at one locus prevent the expression of
alleles at another locus. This interaction is referred to as epistasis.
Example: Flower color in peas
enzyme 1
enzyme 2
AA or Aa
BB or Bb
compound A ¾ ¾ ¾ ®
compound B ¾ ¾ ¾ ® red pigment
An individual with
AA or Aa genotypes will have red flowers. AA or Aa individuals could have white flowers if
the individual also has a "bb" genotype (example: AAbb). In this case, the locus for enzyme 2
prevents the expresson of the locus for enzyme 1.
sometimes an allele is expressed differently if it is
inherited from the mother than if it is inherited from the father.
Example: Huntington's disease is expressed earlier if inherited from the father.
The symptoms of Huntington's disease are caused by a slow deterioration of brain cells
that begins at middle age. It is characterized by involuntary jerking movements of the
body including facial muscles and slurred speech. Later, there is difficulty swallowing,
loss of balance, mood swings, impaired reasoning, and memory loss. The person eventually
dies, usually to pneumonia or heart failure.
A polygenic trait is due to more than one gene locus. It
involves active and inactive alleles.
Active alleles function additively.
Height (tallness) in humans is polygenic but the mechanism of
gene function or the number of genes involved is unknown.
Suppose that there are 3 loci with 2 alleles per locus (A, a, B, b, C, c).
Assume that:
Each active allele (upper case letters: A, B, or C) adds 3 inches of height.
The effect of each active allele is equal, A = B = C.
Males (aabbcc) are 5' tall.
Females (aabbcc) are 4'7".
| Genotype |
Males |
Females |
| aabbcc |
5'0" |
4'7" |
| Aabbcc (or aaBbcc etc.) |
5'3" |
4'10" |
| AaBbcc etc. |
5'6" |
5'1" |
| AaBbCc etc. |
5'9" |
5'4" |
| AaBbCC etc. |
6'0" |
5'7" |
| AaBBCC etc. |
6'3" |
5'10" |
| AABBCC |
6'6" |
6'1" |
The following is a cross between two people of intermediate height.
AaBbCc X AaBbCc
If there is independent assortment, the following gametes will be
produced in equal numbers:
ABC, ABc, AbC, aBC, abC, aBc, Abc, abc
Punnett square analysis:

The Punnett square above can be summarized as follows:
| Genotype |
Males |
Females |
Frequency |
| AABBCC |
6'6" |
6'1" |
1/64 |
| AaBBCC etc. |
6'3" |
5'10" |
6/64 |
| AaBbCC etc. |
6'0" |
5'7" |
15/64 |
| AaBbCc etc. |
5'9" |
5'4" |
20/64 |
| AaBbcc etc. |
5'6" |
5'1" |
15/64 |
| Aabbcc etc. |
5'3" |
4'10" |
6/64 |
| aabbcc |
5'0" |
4'7" |
1/64 |
The frequency column in the table above can be plotted to produce the graph below.

Variability results in a bell-shaped curve (see the diagram above).
Traits with many loci produce many categories. In the example above, 3 loci produced 7
possible heights because a person could have anywhere from 0 to 6 active alleles. If a
trait were determined by 4 loci (AABBCCDD for example) there would be 9 possible
categories because a person could have anywhere from 0 to 8 active alleles.
Variability in polygenic traits can result from genetics and
also from the environment. A measure of the relative contribution of genetics is called heritability.
A trait with a high heritability is determined mostly by genes. A trait with a low
heritability is determined mostly by the environment.
For example, skin pigmentation (darkness) is determined by 2 or 3 pairs of alleles, but
exposure to sunlight (UV radiation) also causes the skin to darken due to the deposition
of protective pigments.
Examples of polygenic traits
stature
performance on IQ tests
skin color
neural tube defects (spina bifida,
anencephaly)
cleft lip/palate
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